Asked by Alex
Can someone show me how to do an indefinate integral?
I have to evaluate this problem.
x^2(3x-1)dx
I have to evaluate this problem.
x^2(3x-1)dx
Answers
Answered by
drwls
First multiply the two terms. Then integrate the terms 3 x^3 and -x^2 separately, and add the results.
Use the rule that the indefinite integral of a*x^n is [a/(n+1)]*x^(n+1),
where a is any constant.
The first term will be (3/4)*x^4. Now integrate -x^2 for the other term. An arbitrary constant C can always be added, but is often omitted.
Use the rule that the indefinite integral of a*x^n is [a/(n+1)]*x^(n+1),
where a is any constant.
The first term will be (3/4)*x^4. Now integrate -x^2 for the other term. An arbitrary constant C can always be added, but is often omitted.
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