Asked by Elena
I am having a lot of trouble doing these types of problems. Can someone show me how to do this. Thank you for your time.
Evaluate the definite integral
4
x(x+3)dx
0
Evaluate the definite integral
4
x(x+3)dx
0
Answers
Answered by
Reiny
expand it first to get
⌠ (x^2 + 3x)dx from 0 to 4
⌡
= (x^3)/3 + (3/2)x from 0 to 4
= 64/3 + 6 - 0
= 82/3
⌠ (x^2 + 3x)dx from 0 to 4
⌡
= (x^3)/3 + (3/2)x from 0 to 4
= 64/3 + 6 - 0
= 82/3
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