Asked by heather
If a tank contains 55.2 g of butane, what volume, in liters, of oxygen is needed to burn all the butane at 0.850 atm and 25 degrees Celsius? Need to show work too.
Answers
Answered by
DrBob222
2C4H10 + 13O2 ==> 8CO2 + 10H2O
mols butane = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols butane to mols O2.
Use PV = nRT and solve for V O2 at the conditions listed.
mols butane = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols butane to mols O2.
Use PV = nRT and solve for V O2 at the conditions listed.
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