When 100mL of 0.60mol per liter K3BO3 is added to 200 mL of 0.40 mol per liter Ca3(BO3)2 Find

Question

When 100mL of 0.60mol per liter K3BO3 is added to 200 mL of 0.40 mol per liter Ca3(BO3)2 Find

a)moles of K3BO
b) moles of Ca(BO3)2
c)final concentration of K+
d)final concentration of Ca+2
e) final concentration of BO3 negative 3

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2 answers
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Answer 1

DrBob222 answered
10 years ago

I'm assuming Ca3(BO3)2 has no Ksp. I couldn't find one.

a. mols = M x L = ?
b. mols = M x L = ?
c. mols K = 3 x mols K3BO3 and (K^+) = mols K/total L
d. mol BO3^3- from K3BO3 = mols K3BO3
mols BO3^3- from Ca3(BO3)2 = 2 x mols Ca3(NO3)2.
Then (BO3^3-) = total mols BO3^3-/total L

Answer 2

Explain Bot answered
11 months ago

To find the answer to these questions, we will need to use the concept of molarity and stoichiometry. Molarity, represented by the symbol M, is a measure of the concentration of a solute in a solution. It is defined as the amount of substance (in moles) divided by the volume of the solution (in liters). The formula for calculating molarity is:

Molarity (M) = moles of solute / volume of solution (in liters)

To solve the given problem, we will follow these steps:

Step 1: Convert the given volume of solutions to liters.
- 100 mL = 100/1000 = 0.1 L
- 200 mL = 200/1000 = 0.2 L

Step 2: Calculate the moles of K3BO3.
- Given concentration of K3BO3 = 0.60 mol/L
- Moles of K3BO3 = concentration * volume
- Moles of K3BO3 = 0.60 mol/L * 0.1 L
- Solution: Moles of K3BO3 = 0.06 mol (a)

Step 3: Calculate the moles of Ca3(BO3)2.
- Given concentration of Ca3(BO3)2 = 0.40 mol/L
- Moles of Ca3(BO3)2 = concentration * volume
- Moles of Ca3(BO3)2 = 0.40 mol/L * 0.2 L
- Solution: Moles of Ca3(BO3)2 = 0.08 mol (b)

Step 4: Calculate the final concentrations.
- Since we are mixing two solutions, the total volume of the final solution is equal to the sum of the volumes of the individual solutions.
- Total volume of final solution = 0.1 L + 0.2 L = 0.3 L

To calculate the final concentration, we will divide the moles of the solute by the total volume of the solution.

(a) Final concentration of K+:
- Divide the moles of K3BO3 by the total volume of the solution.
- Concentration of K+ = moles of K3BO3 / total volume of solution
- Concentration of K+ = 0.06 mol / 0.3 L
- Solution: Final concentration of K+ = 0.20 mol/L (c)

(b) Final concentration of Ca+2:
- Divide the moles of Ca3(BO3)2 by the total volume of the solution.
- Concentration of Ca+2 = moles of Ca3(BO3)2 / total volume of solution
- Concentration of Ca+2 = 0.08 mol / 0.3 L
- Solution: Final concentration of Ca+2 = 0.27 mol/L (d)

(c) Final concentration of BO3-3:
- The number of moles of BO3-3 is the same as the number of moles of Ca3(BO3)2 since the ratio is 1:1.
- Concentration of BO3-3 = moles of Ca3(BO3)2 / total volume of solution
- Concentration of BO3-3 = 0.08 mol / 0.3 L
- Solution: Final concentration of BO3-3 = 0.27 mol/L (e)

To recap:
(a) Moles of K3BO3 = 0.06 mol
(b) Moles of Ca3(BO3)2 = 0.08 mol
(c) Final concentration of K+ = 0.20 mol/L
(d) Final concentration of Ca+2 = 0.27 mol/L
(e) Final concentration of BO3-3 = 0.27 mol/L