Question
What are the axes of symmetry in the graphs of the equations -2x^2 and -2x^2 + 4? I think the vertices are (0,0) and (0,4).
Answers
Reiny
You talk about equations, but show no equation.
You must have meant the equations to be
y = -2x^2 and y = -2x^2 + 4
You are asking for the axes of symmetry but instead state the vertices.
You were correct that the vertices are (0,0) and (0,4) respectively.
so the axes of symmetry are x = 0 for both of them,
that is, the axis of symmetry is the y-axis
You must have meant the equations to be
y = -2x^2 and y = -2x^2 + 4
You are asking for the axes of symmetry but instead state the vertices.
You were correct that the vertices are (0,0) and (0,4) respectively.
so the axes of symmetry are x = 0 for both of them,
that is, the axis of symmetry is the y-axis
Anonymous
Thank you. Yes, I meant to put the y in there. Are the x-intercepts 0 and 4, respectively?
Anonymous
I mean 0 for -2x^2. Sorry about the 4, I didn't mean to put that.
Reiny
yes , the x-intercepts are 0 and 4, respectively
confused about your second reply, the vertices are indeed (0,0) and (0,4)
<<I mean 0 for -2x^2. Sorry about the 4, I didn't mean to put that. >> , don't even know what that is supposed to say.
see,
http://www.wolframalpha.com/input/?i=y+%3D+-2x%5E2+%2C+y+%3D+-2x%5E2+%2B+4
confused about your second reply, the vertices are indeed (0,0) and (0,4)
<<I mean 0 for -2x^2. Sorry about the 4, I didn't mean to put that. >> , don't even know what that is supposed to say.
see,
http://www.wolframalpha.com/input/?i=y+%3D+-2x%5E2+%2C+y+%3D+-2x%5E2+%2B+4