What are the axes of symmetry in the graphs of the equations -2x^2 and -2x^2 + 4? I think the vertices are (0,0) and (0,4).

Answer 1

You talk about equations, but show no equation.
You must have meant the equations to be
y = -2x^2 and y = -2x^2 + 4

You are asking for the axes of symmetry but instead state the vertices.
You were correct that the vertices are (0,0) and (0,4) respectively.

so the axes of symmetry are x = 0 for both of them,
that is, the axis of symmetry is the y-axis

Answer 2

Thank you. Yes, I meant to put the y in there. Are the x-intercepts 0 and 4, respectively?

Answer 3

I mean 0 for -2x^2. Sorry about the 4, I didn't mean to put that.

Answer 4

yes , the x-intercepts are 0 and 4, respectively

confused about your second reply, the vertices are indeed (0,0) and (0,4)

<<I mean 0 for -2x^2. Sorry about the 4, I didn't mean to put that. >> , don't even know what that is supposed to say.

see,
http://www.wolframalpha.com/input/?i=y+%3D+-2x%5E2+%2C+y+%3D+-2x%5E2+%2B+4