Add the separate integrals of the two terms.
The integral of x^4 dx is x^5/5.
The integral of -6 x dx is -6*(1/2)x^2 = -3x^2.
Add an arbitrary constant C to the sum.
(x^5)/5 - 3 x^2 + C
I tried doing this problem, but I have no idea how to do it, can someone show me how to get it done. Thanks.
Evaluate the indefinate integral
(x^4-6x)dx
7 answers
Wait, is that the answer
an would it be (x^5/5) or is the whole rest besides the C on the bottom.
The answer is the last line I wrote
I know, but I don't see what you mean
Is 5-3x^2 all under x^5
Is 5-3x^2 all under x^5
No. 3x^2 and C are separate additive terms. As I said in the beginning, you add the integrals of each term.
so, the answer would be like this
(x^5/5)-3x^2+C
(x^5/5)-3x^2+C
1 answer