Asked by abigail
An isosceles triangle of sides 13cm, 13cm, 10cm is inscribed in a circle. What is the radius of the circle?
Answers
Answered by
Steve
r = 169/24
Answered by
ravin
13*13=169
13-1=12*2=24
169/24=ans
13-1=12*2=24
169/24=ans
Answered by
Victoria
r=169/24
Answered by
Priyanshi
a=13, b=13cm,c=10cs=a+b+c/2 =13+13+10/2 = 36/2= 18cm.
Area of triangle∆= √s(s-a)(s-b)(s-c)
=√18(18-13)(18-13)(18-10)
=√18×5×5×8
=√3600
= 60cm^2
* R= a×b×c/4×Area of∆
= 13×13×10/ 4×60
= 7.02cm 【Ans】
Area of triangle∆= √s(s-a)(s-b)(s-c)
=√18(18-13)(18-13)(18-10)
=√18×5×5×8
=√3600
= 60cm^2
* R= a×b×c/4×Area of∆
= 13×13×10/ 4×60
= 7.02cm 【Ans】
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