Asked by jasmine
A sample of gas has its number of molecules halved, its Kelvin temperature doubled, and its volume halved. What is the new pressure, relative to the original pressure?
Answers
Answered by
Damon
P V = n R T
well, R does not change :)
R = P V/(nT) = P' .5V /(.5n 2T) = P'(.5)V/(nT)
so
.5 P' = P
P' = 2 P
well, R does not change :)
R = P V/(nT) = P' .5V /(.5n 2T) = P'(.5)V/(nT)
so
.5 P' = P
P' = 2 P
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