At the point of fission, a nucleus of 235U that has 92 protons is divided into two smaller spheres, each of which has 46 protons and a radius of 5.11 ✕ 10-15 m. What is the magnitude of the repulsive force pushing these two spheres apart?

Answer 1

F = k Q1 Q2 / d^2
= 9*10^9 * 1.6*10^-19*1.6*10^-19 / (26.1*10^-30)

= .882 * 10^1 = 8.82 Newtons

Answer 2

The answer is 3.5*10^3