Asked by johnson
determine the equation of a circle that has its center a (0,0) and passes through each point.
a)(6,-3)
a)(6,-3)
Answers
Answered by
Steve
well, since the equation will be
x^2+y^2 = r^2
just plug in your values for x and y, and that will give you the necessary r.
x^2+y^2 = r^2
just plug in your values for x and y, and that will give you the necessary r.
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