Question
A force of 15N acts in the forward direction on a carton of 3kg. Suppose a friction force of 6N opposes the carton motion.
Find the following:
1) the net force
2) the acceleration of the carton
Find the following:
1) the net force
2) the acceleration of the carton
Answers
1. 15 - 6 = 9 N. = Net force.
2. a = Fn/m = 9/3 = 3 m/s^2.
2. a = Fn/m = 9/3 = 3 m/s^2.
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