Given that 4^X=8X. Solve for X

Answer 1

tough one!
are you sure you did not mean
4^x = 8^x ?

that would be easy.

What you typed requires some sort of sophisticated method such as "Newton's Method"
but an intuitively obvious answer would be x = 2
however there is another one between 0 and 1

let me know which way it is

Answer 2

Yeah X=2. I just found an answer after 7 hours of solving. You don't need newton's method here. All you need is to apply that basic logarithm rules