Asked by princewill favour
A G.P has 6 terms. If the 3rd and 4th term are 28 and -56 respectively find common ratio, first term and the sum of the G.P.
Answers
Answered by
Reiny
from the given:
term(3) = ar^2 = 28
term(4) = ar^3 = -56
so ar^3/(ar^2) = -56/28
r = -2
then in ar^2 = 28
a(4) = 28
a = 7
sum(6) = a(r^6 - 1)/(r-1)
= 7((-2)^6 - 1)/(-2-1)
= 7(63/-3) = -147
check:
GP is 7, -14 , 28 , - 56 , 112, - 224
sum of that is -147
term(3) = ar^2 = 28
term(4) = ar^3 = -56
so ar^3/(ar^2) = -56/28
r = -2
then in ar^2 = 28
a(4) = 28
a = 7
sum(6) = a(r^6 - 1)/(r-1)
= 7((-2)^6 - 1)/(-2-1)
= 7(63/-3) = -147
check:
GP is 7, -14 , 28 , - 56 , 112, - 224
sum of that is -147
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