Asked by Nicole
The data below has been taken for the reaction of a dye with the hydroxide ion. The reaction was performed at two different hydroxide ion concentrations while the dye concentration was kept constant. What is the rate law?
[OH─] = 0.10 M [OH─] = 0.20 M
t (min) Abs ln(Abs) Abs ln(Abs)
0 1.000 0.000 1.000 0.000
1 0.905 -0.100 0.678 -0.389
2 0.811 -0.209 0.451 -0.796
3 0.735 -0.308 0.288 -1.245
4 0.664 -0.409 0.185 -1.687
I don't even know when to start. Can Someone do generic steps for a problem like this so i can understand how to do them?
[OH─] = 0.10 M [OH─] = 0.20 M
t (min) Abs ln(Abs) Abs ln(Abs)
0 1.000 0.000 1.000 0.000
1 0.905 -0.100 0.678 -0.389
2 0.811 -0.209 0.451 -0.796
3 0.735 -0.308 0.288 -1.245
4 0.664 -0.409 0.185 -1.687
I don't even know when to start. Can Someone do generic steps for a problem like this so i can understand how to do them?
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.