Asked by Monica
A 3.3 kg pendulum bob hangs from a 2 meter string. It is pulled to the side, position A, so that the bob is 103 cm (h on the sketch) above the lowest position, position C. The bob is released and begins to swing.
a) What is its potential energy after it has swung to position B, 27.0 cm below the starting point?
b)How fast is it moving at that point?
a) What is its potential energy after it has swung to position B, 27.0 cm below the starting point?
b)How fast is it moving at that point?
Answers
Answered by
Damon
Pe at top = m g h = 3.3 * 9.81 * 1.03
a) Pe at 1.03-.27 = 3.3 * 9.81 * 0.76
find difference
that difference is Ke in Joules
so
difference = (1/2) m v^2
a) Pe at 1.03-.27 = 3.3 * 9.81 * 0.76
find difference
that difference is Ke in Joules
so
difference = (1/2) m v^2
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