Asked by bob
what is an equation of the conic section x^2+y^2=16 after a rotation of 45 degrees about the origin.
A. (x')^2+(y')^2=16
B. (x')^2- (y')^2=16
C. (x')^2- 2x'y'+(y')^2=16
D. (x')^2+ 2x'y'+(y')^2=16
A. (x')^2+(y')^2=16
B. (x')^2- (y')^2=16
C. (x')^2- 2x'y'+(y')^2=16
D. (x')^2+ 2x'y'+(y')^2=16
Answers
Answered by
Steve
think. It's a circle. Invariant under rotation about its center.
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