Asked by chelsey
Sometimes the basicity of a solution is reported using pOH (pOH = -log[OH-]). What is the
a. [OH-] if pOH = 1.90
b. [H3O+] if pOH = 12.94
c. pH if pOH = 9.70
a. [OH-] if pOH = 1.90
b. [H3O+] if pOH = 12.94
c. pH if pOH = 9.70
Answers
Answered by
DrBob222
If you know H^+ or OH^- the other can be calculated from
(H^+)(OH^-) = Kw = 1E-14
If you want pH
pH = -log(H^+)
If you want pOH
pOH = -log(OH^-)
If yo have pH or pOH and want the other one
pH + pOH = pKw = 14
(H^+)(OH^-) = Kw = 1E-14
If you want pH
pH = -log(H^+)
If you want pOH
pOH = -log(OH^-)
If yo have pH or pOH and want the other one
pH + pOH = pKw = 14