Asked by chelsey
Sometimes the basicity of a solution is reported using pOH (pOH = -log[OH-]). What is the
a. [OH-] if pOH = 1.90
b. [H3O+] if pOH = 12.94
c. pH if pOH = 9.70
a. [OH-] if pOH = 1.90
b. [H3O+] if pOH = 12.94
c. pH if pOH = 9.70
Answers
Answered by
DrBob222
If you know H^+ or OH^- the other can be calculated from
(H^+)(OH^-) = Kw = 1E-14
If you want pH
pH = -log(H^+)
If you want pOH
pOH = -log(OH^-)
If yo have pH or pOH and want the other one
pH + pOH = pKw = 14
(H^+)(OH^-) = Kw = 1E-14
If you want pH
pH = -log(H^+)
If you want pOH
pOH = -log(OH^-)
If yo have pH or pOH and want the other one
pH + pOH = pKw = 14
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.