Asked by Mohanad

A shopper pushes a grocery cart 20.0 m at constant speed on level
ground, against a 35.0 N frictional force. He pushes in a direction 25.0º
below the horizontal. (a) What is the work done on the cart by friction? (b)
What is the work done on the cart by the gravitational force? (c) What is
the work done on the cart by the shopper? (d) Find the force the shopper
exerts, using energy considerations. (e) What is the total work done on
Answered by Damon
Fx = 35 cos 25

friction work = -35 cos 25 (20)

gravity does none, not in the direction of motion

same as friction work but positive sign

Fx = friction work /20
and
F = Fx/cos 25

total work is friction work since no vertical motion
Answered by andrea lee
-34.999
Answered by steve
the guy who answered the first isnt correct
Answered by steve
there should be no cos for friction force
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