Asked by LT
                For there reaction system involving the species in the table below, what conclusion is
justified for standard state conditions?
Standard Reduction Potentials E0
2Fe3+ + Sn2+ ¡ú 2Fe2+ + Sn4+ +0.62 V
Sn2+ + I2 ¡ú Sn4+ + 2I¨C +0.38 V
(A) I¨C would react with Fe3+
(B) Fe2+ would react with I2
(C) Fe3+ is a weaker oxidizing agent than I2
(D) Fe2+ is a stronger reducing agent than I¨C
            
            
        justified for standard state conditions?
Standard Reduction Potentials E0
2Fe3+ + Sn2+ ¡ú 2Fe2+ + Sn4+ +0.62 V
Sn2+ + I2 ¡ú Sn4+ + 2I¨C +0.38 V
(A) I¨C would react with Fe3+
(B) Fe2+ would react with I2
(C) Fe3+ is a weaker oxidizing agent than I2
(D) Fe2+ is a stronger reducing agent than I¨C
Answers
                    Answered by
            DrBob222
            
    My screen is gibberish again on both .
    
                    Answered by
            DrBob222
            
    I'm wondering if you are using a Mac.
    
                    Answered by
            LT
            
    2Fe3+ + Sn2+ ¡ú 2Fe2+ + Sn4+ +0.62 V
Sn2+ + I2 ¡ú Sn4+ + 2I¨C +0.38 V
    
Sn2+ + I2 ¡ú Sn4+ + 2I¨C +0.38 V
                    Answered by
            LT
            
    man this sucks well hold on 
2Fe3+ + Sn2+ --> 2Fe2+ + Sn4+ +0.62 V
Sn2+ + I2 --> Sn4+ + 2I– +0.38 V
i hope this is better
    
2Fe3+ + Sn2+ --> 2Fe2+ + Sn4+ +0.62 V
Sn2+ + I2 --> Sn4+ + 2I– +0.38 V
i hope this is better
                    Answered by
            DrBob222
            
    Yes. That's better but I don't have time to look at it now. I'll get back later.
    
                    Answered by
            DrBob222
            
    But you also need to redo the answers because they contain some of the same strange symbols. especially the A answer.
    
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