Asked by LT
For there reaction system involving the species in the table below, what conclusion is
justified for standard state conditions?
Standard Reduction Potentials E0
2Fe3+ + Sn2+ ¡ú 2Fe2+ + Sn4+ +0.62 V
Sn2+ + I2 ¡ú Sn4+ + 2I¨C +0.38 V
(A) I¨C would react with Fe3+
(B) Fe2+ would react with I2
(C) Fe3+ is a weaker oxidizing agent than I2
(D) Fe2+ is a stronger reducing agent than I¨C
justified for standard state conditions?
Standard Reduction Potentials E0
2Fe3+ + Sn2+ ¡ú 2Fe2+ + Sn4+ +0.62 V
Sn2+ + I2 ¡ú Sn4+ + 2I¨C +0.38 V
(A) I¨C would react with Fe3+
(B) Fe2+ would react with I2
(C) Fe3+ is a weaker oxidizing agent than I2
(D) Fe2+ is a stronger reducing agent than I¨C
Answers
Answered by
DrBob222
My screen is gibberish again on both .
Answered by
DrBob222
I'm wondering if you are using a Mac.
Answered by
LT
2Fe3+ + Sn2+ ¡ú 2Fe2+ + Sn4+ +0.62 V
Sn2+ + I2 ¡ú Sn4+ + 2I¨C +0.38 V
Sn2+ + I2 ¡ú Sn4+ + 2I¨C +0.38 V
Answered by
LT
man this sucks well hold on
2Fe3+ + Sn2+ --> 2Fe2+ + Sn4+ +0.62 V
Sn2+ + I2 --> Sn4+ + 2I– +0.38 V
i hope this is better
2Fe3+ + Sn2+ --> 2Fe2+ + Sn4+ +0.62 V
Sn2+ + I2 --> Sn4+ + 2I– +0.38 V
i hope this is better
Answered by
DrBob222
Yes. That's better but I don't have time to look at it now. I'll get back later.
Answered by
DrBob222
But you also need to redo the answers because they contain some of the same strange symbols. especially the A answer.