Asked by peterson
75.0 g of H2O at 23.0 oC is added to 100.0 g of H2O at 67.5 oC.
What is the temperature of the resulting mixture?
What is the temperature of the resulting mixture?
Answers
Answered by
DrBob222
Heat gained by cool water + heat lost by warm water = 0.
[mass cool H2O x specific heat H2O x (Tfinal-Tinitial)] + [mass water H2O x specific heat warm H2O x (Tfinal-Tinitial)] = 0
Substitute and solve for T final.
[mass cool H2O x specific heat H2O x (Tfinal-Tinitial)] + [mass water H2O x specific heat warm H2O x (Tfinal-Tinitial)] = 0
Substitute and solve for T final.
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