acceleration=force/total mass=.03N/.06kg= .5m/s^2
forceonthetoy=mass*a=.05*.5=.025N
3.0 x 10^(–2)-N force is applied horizontally to the free end, the force of the string on the toy, at the other end, is:
A) 0.15 N
B) 6.0 x 10^(–3) N
C) 2.5 x 10^(–2) N
D) 3.0 x 10^(–2) N
E) 3.5 x 10^(–2) N
forceonthetoy=mass*a=.05*.5=.025N
acceleration=force/total mass=.03N/.06kg= .5m/s^2
forceonthetoy=mass*a=.05*.5=.025N
Since there is no friction on the surface, the force of the string pulling the toy should be equal to the force applied.
So, the force of the string on the toy would be 3.0 x 10^(–2) N.
Therefore, the correct answer would be D) 3.0 x 10^(–2) N.
Force = mass × acceleration
The mass of the toy is 50 g, which is equivalent to 0.050 kg. The force applied by the string is 3.0 × 10^(-2) N, and the acceleration is given by dividing the force by the mass:
acceleration = Force / mass
Now we can substitute the values into the equation:
acceleration = 3.0 × 10^(-2) N / 0.050 kg
Calculating this gives:
acceleration = 0.60 m/s^2
Since the surface is frictionless, there are no other forces acting on the toy apart from the force applied by the string. Therefore, the force of the string on the toy is equal to the mass of the toy multiplied by the acceleration:
Force = mass × acceleration
Force = 0.050 kg × 0.60 m/s^2
Evaluating this expression gives:
Force = 0.030 N
Therefore, the force of the string on the toy is 0.030 N, which is equivalent to 3.0 × 10^(-2) N.
So the correct answer is option D) 3.0 × 10^(-2) N.