Asked by Tully
A 0.380 kg pendulum bob passes through the lowest part of its path at a speed of 2.03 m/s. What is the tension in the pendulum cable at this point if the pendulum is 83.1 cm long?
When the pendulum reaches its highest point, what angle does the cable make with the vertical?
What is the tension in the pendulum cable when the pendulum reaches its highest point?
When the pendulum reaches its highest point, what angle does the cable make with the vertical?
What is the tension in the pendulum cable when the pendulum reaches its highest point?
Answers
Answered by
bobpursley
tension=mg+ma=mg+mv^2/r=you do it.
at hightest point, gain of PE= KE at bottom,
gain of PE=1/2 .380*2.03^2/.831
mgh=gain of PE
h=gainofPE/(.380*9.8)
cos Theta= (r-h) /r
tension at highest point. mg*cosTheta
at hightest point, gain of PE= KE at bottom,
gain of PE=1/2 .380*2.03^2/.831
mgh=gain of PE
h=gainofPE/(.380*9.8)
cos Theta= (r-h) /r
tension at highest point. mg*cosTheta
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