r' = 2.4/(3t+6)
r = 0.8 log(3t+6)+c
solve for c at t=0 in
0.8 log6 + c = 3.8
now just plug in t=16 for the final answer.
At a summer campfire, the radius of a marshmallow on a stick expands at the rate of
\ {r ' (t)} = \frac{2.4 }{3 t + 6} mm/s
where t is the time of heating in seconds. Initially the radius was 3.8 mm. Find the radius after 16 seconds using the following steps:
When substituting,
du =______ dt
The resulting integral looks like \int \frac{A}{u} \, du where A is a numerical value.
A = _______
The constant of integration, C is
The radius after 16 seconds is
_______mm
1 answer
1 answer