There are 89 two-digit numbers (10-99). The tens digits are higher in 10, 20, 21, 30, 31, 32 etc.
Count them up.
How many two-digit numbers have a tens digit that is greater than the units digit? Explain.
8 answers
45 NUMBERS
What of the solution ?
Please solve it ?
Thanks
Thanks
Abi to yarere ?
Are you mad google ?
Translated for you
Are you mad google ?
Translated for you
It is absolutely correct
Awesome
Awesome
You
45 numbers,
Notice that for each tens digit from 10, the number of unit digits smaller than the tens digit goes up by 1. The number of unit digits that are smaller than the tens digit in “10s” is 1. There is 2 in the “20s”, 3 in the “30s” and so on all the way up to 90. So, it’s 1+2+3+4+5+6+7+8+9=45
Hope this helps!
Notice that for each tens digit from 10, the number of unit digits smaller than the tens digit goes up by 1. The number of unit digits that are smaller than the tens digit in “10s” is 1. There is 2 in the “20s”, 3 in the “30s” and so on all the way up to 90. So, it’s 1+2+3+4+5+6+7+8+9=45
Hope this helps!
3 answers