Question
In the chemical reaction, .
Zn(s) + CuSO4(aq) ¨ ZnSO4(aq) + Cu(s),
(A) metallic zinc is the reducing agent.
(B) metallic zinc in reduced.
(C) copper ion is oxidized.
(D) sulfate ion is the oxidizing agent.
Zn(s) + CuSO4(aq) ¨ ZnSO4(aq) + Cu(s),
(A) metallic zinc is the reducing agent.
(B) metallic zinc in reduced.
(C) copper ion is oxidized.
(D) sulfate ion is the oxidizing agent.
Answers
Remember the definitions.
Oxidation is the loss of electrons.
Reduction is the gain of electrons.
(The material oxidized is the reducing agent; therefore, the reducing agent loses electrons. The material reduced is the oxidizing agent; therefore, the oxidizing agent gains electrons).
Zn is zero on the left and +2 on the right.
Cu is +2 on the left and zero on the right.
S is +6 on both sides.
O is -2 on both sides.
From those definitions AND I have given you the oxidation states, you should be able to pick out the answer.
Oxidation is the loss of electrons.
Reduction is the gain of electrons.
(The material oxidized is the reducing agent; therefore, the reducing agent loses electrons. The material reduced is the oxidizing agent; therefore, the oxidizing agent gains electrons).
Zn is zero on the left and +2 on the right.
Cu is +2 on the left and zero on the right.
S is +6 on both sides.
O is -2 on both sides.
From those definitions AND I have given you the oxidation states, you should be able to pick out the answer.
is the answer C
The answer is not C.
The reaction shows Cu going from Cu^+2 to Cu or from +2 to zero. That is the gain of electrons. Oxidation is the loss of electrons. It can't be C.
The reaction shows Cu going from Cu^+2 to Cu or from +2 to zero. That is the gain of electrons. Oxidation is the loss of electrons. It can't be C.
Then A because its going from 0 to +2
Right. Metallic Zn is the reducing agent (it is oxidized in the process).
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