Yes, it's endothermic and you're right for the reason, too.
The equation tells you that 43.2 kcal is consumed by 1 mol N2 (28g). All you need to do is proportion that out for 50 g.
43.2 kcal x (50/28) = ?
Consider the reaction N2+O2-->2NO with Delta H=43.2kcal.
When 50.0g of N2 react with an excess of oxygen, how much heat is generated/consumed?
I know that this is an endothermic reaction b/c of the + delta H, is there some sort of formula to use here? I have no idea where to start...can someone walk me through this? I'm lost!!!
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