Asked by Linda
A gas occupies a volume of .350 L at a temperature of 18.0 degrees Celsius and a pressure of 980.0 torr. What will be the volume of this gas at standard conditions? Please explain how to do it.
Answers
Answered by
Damon
p v = n R T
n and R the same
so
P1 V1/T1 = P2 V2/T2
T1 = 18 + 273
T2 = 273
P1 = 980 Torr
P2 = 760 Torr
V1 = .35
V2 = ?
n and R the same
so
P1 V1/T1 = P2 V2/T2
T1 = 18 + 273
T2 = 273
P1 = 980 Torr
P2 = 760 Torr
V1 = .35
V2 = ?
Answered by
Linda
Why are n and R the same? Isn't n the mol's and R the ideal gas constant?
Answered by
DrBob222
Damon used PV = nRT. n isn't known at the conditions listed. Using those conditions allows the evaluation of n. Then that value of n is used in another PV = nRT calculation to solve for the volume at the new conditions.
You can avoid that problem if you use
(P1V1/T1) = (P2V2/T2) and just one calculation.
To answer your question, yes, n is mols and R is constant. The P1V1/T1 = P2V2/T2 avoids the use of both n and R although they are used inherently (perhaps intrinsically is a better word).
You can avoid that problem if you use
(P1V1/T1) = (P2V2/T2) and just one calculation.
To answer your question, yes, n is mols and R is constant. The P1V1/T1 = P2V2/T2 avoids the use of both n and R although they are used inherently (perhaps intrinsically is a better word).
Answered by
Linda
Okay, I understand that part, but if I use P1V1=P2V2, what happens to the temperature that they gave me? What do I do with it?
Answered by
DrBob222
I don't see a P1V1 = P2V2.
I see a (P1V1/T1) = (P2V2/T2) so the T is taken into account.
I see a (P1V1/T1) = (P2V2/T2) so the T is taken into account.
Answered by
Linda
Oh okay, my bad, and thank you for your help
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