acceleration= v^2/r=
= (2pir/period)^2/r= 2PI*(r)/period^2
no change 90 min to seconds, and 4175 miles to meters, and you have it.
A satellite that is 4175 miles from the center of the earth, orbits with a period of 90 minutes. What is its centripetal acceleration?
2 answers
F = G M m/r^2 = m Ac
so
Ac = G M/r^2
G = 6.67 * 10^-11
M = 6 * 10^24 kg
Copy this
4175 miles = meters
into a Google search box and get
r = 6.72*10^6 meters
and 90 minutes is 5,400 seconds
so
Ac = G M/r^2
G = 6.67 * 10^-11
M = 6 * 10^24 kg
Copy this
4175 miles = meters
into a Google search box and get
r = 6.72*10^6 meters
and 90 minutes is 5,400 seconds
1 answer