Asked by Anonymous
Boy throws a penny into a wishing well at a velocity of 2 m/s and at an angle of 45 degrees below horizontal. If the penny takes 1.3 seconds to hit the water, how deep is the well?
Answers
Answered by
Henry
Vo = 2m/s[-45o]
Xo=2*cos(-45)=1.414 m/s=Hor. component.
Yo=2*sin(-45)=-1.414 m/s=Ver. component.
Depth = Yo*t + 0.5g*t^2 =
-1.414*1.3 + 4.9*1.3^2 = 6.44 m.
Xo=2*cos(-45)=1.414 m/s=Hor. component.
Yo=2*sin(-45)=-1.414 m/s=Ver. component.
Depth = Yo*t + 0.5g*t^2 =
-1.414*1.3 + 4.9*1.3^2 = 6.44 m.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.