Asked by Jnr John
An isosceles triangle ABC has two sides 17cm in length and a base 10cm in length. Find the size of the angle between the equal sides.
Answers
Answered by
Steve
Draw the altitude to the base. Then, if the angle is x,
sin(x/2) = 5/17
now you know x/2, so just double it.
sin(x/2) = 5/17
now you know x/2, so just double it.
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