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y = x^3 sinx / 5cosx
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what about it ?
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Prove the following:
[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
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x^3(sinx)/ 5cosx
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2(sinx)^2-5cosx-4=0
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2(sinx)^2-5cosx-4=0
Solve for all solutions between [0,2pi]
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