Question
If 0.08 mol of LiCl is added to a one liter solution that has dissolved 0.01 mol of PbCl2, will a precipitate
occur?
occur?
Answers
DrBob222
0.01 mol PbCl2 is dissolved.
+0.08 mol LiCl.
Total Cl = 0.08 + 2*0.01) = 0.1 mol Cl
Then Kquotient = (Pb^2+)(Cl^-)^2 = (0.01)(0.1)^2 = 1E-4. Is that greater or less than Ksp? If greater, yes a ppt will occur. If less no it will not occur.
+0.08 mol LiCl.
Total Cl = 0.08 + 2*0.01) = 0.1 mol Cl
Then Kquotient = (Pb^2+)(Cl^-)^2 = (0.01)(0.1)^2 = 1E-4. Is that greater or less than Ksp? If greater, yes a ppt will occur. If less no it will not occur.