Asked by Lena
what volume of concentrated 18M H2SO4 is required to prepare 250mL of a 6.0M solution?
how would you solve this problem? i know it has something to do with the molarity formula but no idea how to apply it
how would you solve this problem? i know it has something to do with the molarity formula but no idea how to apply it
Answers
Answered by
DrBob222
Use the dilution formula of
c1v1 = c2v2
18M*vmL = 6M*250mL
v = ?mL.
c1v1 = c2v2
18M*vmL = 6M*250mL
v = ?mL.
Answered by
Lena
so v would be 83mL?
Answered by
Damon
well, if I had one liter of the final stuff I would have 6 mols of H2SO4 in it
so in 250 mL I need 6/4 or 1.5 mols H2SO4
so the real question is:
What volume of 18M H2SO4 contains 1.5 mols of H2SO4
well there are 18 in a liter
so
I need 1.5/18 liter =.08333...... Liter which is 83 mL
so in 250 mL I need 6/4 or 1.5 mols H2SO4
so the real question is:
What volume of 18M H2SO4 contains 1.5 mols of H2SO4
well there are 18 in a liter
so
I need 1.5/18 liter =.08333...... Liter which is 83 mL
Answered by
Lena
ohh okay now i understand. thank you
Answered by
Damon
You are welcome :)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.