a rock with a mass of 2 kg is thrown from the top of a cliff 75 m high with a velocity of 10m/s. how much Kinetic energy does it have when it gets to the bottom?

2 answers

V^2 = Vo^2 + 2g*h
V^2 = !0^2 + 19.6*75 = 1570
V = 39.62 m/s
KE = 0.5m*V^2 = 1*39.62^2 = 1570 J.
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