Asked by andrew
chance+of+winning+if+you+play+10+times+what+is+the+probability+of you+winning+once if you have a 10% chance of winning each time
Answers
Answered by
Damon
binomial dist
P(k wins in n trials)
= C(n,k) p^k (1-p)^(n-k)
C(10,1) = 10 because
C(n,k) = n!/[k!(n-k)!]
p = .1
1-p = .9
so
P(10,1) = 10 *.1^1 *.9^9
= .387
P(k wins in n trials)
= C(n,k) p^k (1-p)^(n-k)
C(10,1) = 10 because
C(n,k) = n!/[k!(n-k)!]
p = .1
1-p = .9
so
P(10,1) = 10 *.1^1 *.9^9
= .387
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