Solve the following equation for x in terms of ln and e.

(2e^3)-6-(16e^-x)=0

2 answers

just chug away as usual

2e^3 - 6 - 16e^-x = 0
16e^-x = 2e^3 - 6
e^-x = (e^3-3)/8
e^x = 8/(e^3-3)
x = ln(8/(e^3 - 3))
Thank you!
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