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Find sin 2x, cos 2x, and tan 2x from the given infomation csc x=4, tan x < 0Asked by Kaylee
Find sin 2x, cos 2x, and tan 2x from the given infomation
csc x=4, tan x < 0
csc x=4, tan x < 0
Answers
Answered by
Steve
csc positive, tan negative means QII
since sinx = 1/cscx,
sinx = 1/4
cosx = √15/4
tanx = 1/√15
Now just apply your double-angle formulas
since sinx = 1/cscx,
sinx = 1/4
cosx = √15/4
tanx = 1/√15
Now just apply your double-angle formulas
Answered by
Kaylee
thanks but I'm still stumped by what they mean about how and what the double angle formula is. The double angle formula confuses me
Answered by
Steve
sin2x = 2 sinx cosx
= 2(1/4)(√15/4) = 2√15/16
cos2x = cos^2x - sin^2 x
= 15/16 - 1/16 = 7/8
tan2x = 2tanx/(1-tan^2 x)
= 2/√15 / (1 - 1/15)
= 2/√15 * 15/14
= √15/7
= 2(1/4)(√15/4) = 2√15/16
cos2x = cos^2x - sin^2 x
= 15/16 - 1/16 = 7/8
tan2x = 2tanx/(1-tan^2 x)
= 2/√15 / (1 - 1/15)
= 2/√15 * 15/14
= √15/7
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