Question

Determine the sulfate ion concentration in a solution prepared by diluting 15.00mL of a 0.200M aluminum sulfate solution with 35.00mL of water. Assume the volumes are additive.
[Al2(SO4)3] = 0.200M x (15.00/50.00) = ?
Then [SO4^2-] = 3x that.

Related Questions

What is the molarity of the final solution of 2.00mL of the 5.00M stock solution is diluted to 10.00... What is the molarity of the final solution if 2.00mL of the 5.00 M stock solution is diluted to 10.0... the lead (II) nitrate in 25.49 ml of a 0.1338M solution reacts with all of the aluminum sulfate in 2... What formula would you use to solve this problem? I'm stuck. You have prepared a solution by dilu...