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when magnesium chlorate under goes decompostion, oxgen gas is realsed in the following reaction: 2KClO3→ 2KCl + 3O2 when 3.50 g...Asked by katie
magnesium chlorate under goes decompostion, oxgen gas is realsed in the following reaction:
2KClO3 → 2KCl + 3O2
when 3.50 grams of potassuim chlorate is decomposed at STP, how many litters of oxgen will be produced?
2KClO3 → 2KCl + 3O2
when 3.50 grams of potassuim chlorate is decomposed at STP, how many litters of oxgen will be produced?
Answers
Answered by
DrBob222
Two errors to point out. You say magnesium chlorate but use potassium chlorate. Second, L is liters, not litters (as in a litter of puppies).
Convert grams KClO3 to mols. mols = grams/molar mass
Using the coefficients in the balanced equation, convert mols KClO3 to mols O2.
Then convert mols O2 to L. 22.4 L/mol x mols = ?L
Convert grams KClO3 to mols. mols = grams/molar mass
Using the coefficients in the balanced equation, convert mols KClO3 to mols O2.
Then convert mols O2 to L. 22.4 L/mol x mols = ?L
Answered by
bobpursley
It will be 22.4 x 3/2 x the moles of KClO3
moles KClO3= 3grams/molmasspotassiumchlorate
moles KClO3= 3grams/molmasspotassiumchlorate
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