Asked by Hayla
A buffer solution is prepared by mixing 99.0 mL of 0.450 M HF and 55.0 mL of 1.15 M NaF. Determine the pH of the solution after the addition of 0.01 moles NaOH (assume there is no change in volume when the NaOH is added).
Answers
Answered by
DrBob222
millimols HF = mL x M = approx 44.55
mmols NaF = approx 63.25
0.01 mols = 10 mmols NaOH added
..........HF + OH^- ==> F^- + H2O
I........44.55..0.......63.25......
add............10............
C........-10...-10......10
E.......34.55...0......73.25
Plug the E line into the Henderson-Hasselbalch equation and solve for pH.
mmols NaF = approx 63.25
0.01 mols = 10 mmols NaOH added
..........HF + OH^- ==> F^- + H2O
I........44.55..0.......63.25......
add............10............
C........-10...-10......10
E.......34.55...0......73.25
Plug the E line into the Henderson-Hasselbalch equation and solve for pH.