A long jumper leaves the ground at an angle of 20 degrees above horizontal and at a speed of 11m/s..how far does he jump?

Answers

Answered by bobpursley
time in air:

hf=ho+vo*sin20*t-4.9t^2
hf,ho=0, vo given 11m/s solve for time.
Now, how far
d=voCos20*time

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