Asked by Monique

For all real numbers, f(x)=(x^2+1)/2. If f(a)=25 and f(11)=b, what could be the value of b-a?

I'm confused on how you do these problems. Can someone show me how to do them? Thanks much!
Answered by bobpursley
I will start you on b

f(11)=(11^2+1)/2=61 so b is 61

25=(a^2+1)/2 solve for a....
Answered by Monique
Ok, so f(25)=(25^2+1)/2. 626/2=313. So, a=313. When substituted, 61-313 is -252.

There's a small issue though. This question is multiple, and I don't see a -252 as one of the choices:

a. -14
b. 36
c. 68
d. 77
e. 86

Did I do something wrong?
Answered by Steve
Shoot I answered this and answer didn't save
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