Question
For all real numbers, f(x)=(x^2+1)/2. If f(a)=25 and f(11)=b, what could be the value of b-a?
I'm confused on how you do these problems. Can someone show me how to do them? Thanks much!
I'm confused on how you do these problems. Can someone show me how to do them? Thanks much!
Answers
bobpursley
I will start you on b
f(11)=(11^2+1)/2=61 so b is 61
25=(a^2+1)/2 solve for a....
f(11)=(11^2+1)/2=61 so b is 61
25=(a^2+1)/2 solve for a....
Monique
Ok, so f(25)=(25^2+1)/2. 626/2=313. So, a=313. When substituted, 61-313 is -252.
There's a small issue though. This question is multiple, and I don't see a -252 as one of the choices:
a. -14
b. 36
c. 68
d. 77
e. 86
Did I do something wrong?
There's a small issue though. This question is multiple, and I don't see a -252 as one of the choices:
a. -14
b. 36
c. 68
d. 77
e. 86
Did I do something wrong?
Steve
Shoot I answered this and answer didn't save