Asked by Monique
For all real numbers, f(x)=(x^2+1)/2. If f(a)=25 and f(11)=b, what could be the value of b-a?
I'm confused on how you do these problems. Can someone show me how to do them? Thanks much!
I'm confused on how you do these problems. Can someone show me how to do them? Thanks much!
Answers
Answered by
bobpursley
I will start you on b
f(11)=(11^2+1)/2=61 so b is 61
25=(a^2+1)/2 solve for a....
f(11)=(11^2+1)/2=61 so b is 61
25=(a^2+1)/2 solve for a....
Answered by
Monique
Ok, so f(25)=(25^2+1)/2. 626/2=313. So, a=313. When substituted, 61-313 is -252.
There's a small issue though. This question is multiple, and I don't see a -252 as one of the choices:
a. -14
b. 36
c. 68
d. 77
e. 86
Did I do something wrong?
There's a small issue though. This question is multiple, and I don't see a -252 as one of the choices:
a. -14
b. 36
c. 68
d. 77
e. 86
Did I do something wrong?
Answered by
Steve
Shoot I answered this and answer didn't save
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.