Asked by Chloe
1.) Solve for x. 2x(x - 12) = -40
2.) Solve for x. 3x2 + 2x = 12 - 7x
3.) Simplify the expression. 8sqrt[-63]
4.) Find the absolute value of the complex number. Abs Val [7 + 24i]
5.) Simplify the expression. [4 - 7i] + [2 + 3i]
Thank you so much!! :)
2.) Solve for x. 3x2 + 2x = 12 - 7x
3.) Simplify the expression. 8sqrt[-63]
4.) Find the absolute value of the complex number. Abs Val [7 + 24i]
5.) Simplify the expression. [4 - 7i] + [2 + 3i]
Thank you so much!! :)
Answers
Answered by
Steve
#1
2x(x-12) = -40
x(x-12) + 20 = 0
x^2-12x+20 = 0
(x-2)(x-10) = 0
#2
3x^2 + 2x = 12 - 7x
3x^2 + 9x - 12 = 0
x^2+3x-4 = 0
(x+4)(x-1) = 0
#3
8√-63 = 8√63 i
#4
|7+24i| = √(7^2 + 24^2) = 25
#5
(4-7i)(2+3i) = 8 - 14i + 12i - 21i^2 = 29-2i
2x(x-12) = -40
x(x-12) + 20 = 0
x^2-12x+20 = 0
(x-2)(x-10) = 0
#2
3x^2 + 2x = 12 - 7x
3x^2 + 9x - 12 = 0
x^2+3x-4 = 0
(x+4)(x-1) = 0
#3
8√-63 = 8√63 i
#4
|7+24i| = √(7^2 + 24^2) = 25
#5
(4-7i)(2+3i) = 8 - 14i + 12i - 21i^2 = 29-2i
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