Question

q = f(p) = 10300e^−0.34p

a) Find the number of products sold when the price of the product is $5. (Round your answer to the nearest whole number.)
Number of products sold:

b) Find a formula for the rate of change in the number of products sold when the price is p dollars.
fŒ(p) =

c) What is the rate of change in the number of products sold when the price is $5? (Round your answer to one decimal place.)
Rate of Change:

Answer 1

by the time you get to calculus, you certainly should know how to plug in a value and evaluate a function! Where do you get stuck?

(a) q(5) = 10300*e^(-0.34*5) = 1882

(b) as you know, if
y = e^u
y' = e^u u'
And, as you know, the derivative is the rate of change.
So, q' = 10300*e^(-0.34p)(-.34) = -3502e^(-.34p)

(c) now plug in p=5 to get q'(5)

extra credit: what does it mean that q'(p) is negative?

Answer 2

satisfy but not enough