Asked by lola
a 5% acid solution is mixed with a 9% acid solution. How many ounces of each solution are needed to obtain 40 ounces of a 6% solution?
Answers
Answered by
Steve
the amount of acid in each part must total the acid in the mixture, so
.05x + .09(40-x) = .06(40)
Now just solve for x, the amount of 5% acid.
.05x + .09(40-x) = .06(40)
Now just solve for x, the amount of 5% acid.
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