Question

Consider 10 independent tosses of a biased coin with the probability of Heads at each toss equal to p, where 0<p<1.

Let A be the event that there are 6 Heads in the first 8 tosses. Let B be the event that the 9th toss results in Heads.

Find P(B∣A) and express it in terms of p using standard notation

Answer 1

Huh? if the probability of a toss being heads is .5 then it is .5 no matter what happened earlier.

Answer 2

1 = p

2 = 12*p^5*(1-p)^2

3 = 0.2571428571

4a = 15

4b = 60

4c = 6

4d = 4

4e = 10

4f = 5

Answer 3

mit2020
4a 30 =a
4b 4=b
4c 8 =c
4d 2=d