Consider 10 independent tosses of a biased coin with the probability of Heads at each toss equal to p, where 0<p<1.
Let A be the event that there are 6 Heads in the first 8 tosses. Let B be the event that the 9th toss results in Heads.
Find P(B∣A) and express it in terms of p using standard notation
3 answers
Huh? if the probability of a toss being heads is .5 then it is .5 no matter what happened earlier.
1 = p
2 = 12*p^5*(1-p)^2
3 = 0.2571428571
4a = 15
4b = 60
4c = 6
4d = 4
4e = 10
4f = 5
2 = 12*p^5*(1-p)^2
3 = 0.2571428571
4a = 15
4b = 60
4c = 6
4d = 4
4e = 10
4f = 5
mit2020
4a 30 =a
4b 4=b
4c 8 =c
4d 2=d
4a 30 =a
4b 4=b
4c 8 =c
4d 2=d