Asked by Anonymous

A 2 kg block, starting from the rest, slides 20 m down frictionless inclined plane, dropping a distance of 10m.

The magnitude of the net force on the block while it is sliding is...?

How do I solve this problem?

And if it were to ask for the speed at the bottom of the incline, how would I find that?
Thanks!
Answered by bobpursley
The force down the plane is mgSinTheta or mg (1/2). The speed will be ...

Vf^=2 a d = 2*1/2 mg/m

vf= sqrt g

check my reasoning.
Answered by Ali jamal
Teacher
Answered by pissbaby
Teache
Answered by pissbaby2
Teach
Answered by pissbaby3
Teac
Answered by pissbaby4
Tea
There are no AI answers yet. The ability to request AI answers is coming soon!