Asked by Anonymous
On a day when atmospheric pressure if 76cmHg, the pressure gauge on the tank reads the pressure inside to be 400cmHg. the gas in the tank has a temperature of 9 degrees celcuis. If the tank is heated to 31 degrees celcuis by the sun, and no gas exists, what will the pressure gauge read?
Answers
Answered by
Damon
P V = n R T
P/T = n R/V = constant here
T1 = 273 + 9
T2 = 273 + 31
P1 = 76 + 400
P2 = 76 + x where x is new gage pressure
P2/T2 = P1/T1
so P2 = (T2/T1) P1
x = P2 - 76
P/T = n R/V = constant here
T1 = 273 + 9
T2 = 273 + 31
P1 = 76 + 400
P2 = 76 + x where x is new gage pressure
P2/T2 = P1/T1
so P2 = (T2/T1) P1
x = P2 - 76
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.