A 1.60 meter tall woman is standing at the bottom of a freshwater pool. If the bottom pool is 8.00 meters deep, what is the pressure difference between the woman's feet and the top of her head?

3 answers

rho g h = 1000 kg/m^3 * 9.81 m/s^2 * 1.6 m in Pascals
depth does not matter, looking for difference
So does this mean that when you multpily it all, 15,969 is the pressure difference between her head and her feet?
That sounds about right.

One atmosphere is about 101,325 Pascals
that is about 10 meters of water
so about 10,000 Pascals/meter