Asked by Help a girl out

(49w^5-28w^3)/7w
Answered by Steve
can you not compute

49/7 28/7 w^5/w and w^3/w?

Just divide each term by 7 and by w.

Hint: when dividing powers, subtract exponents.
Answered by Anonymous
@Steve How do I divide each term? and then subtract? Its Dividing Binomials by Monomials. It says you have to find the quotient.
Answered by @Steve
Can you please help me? I tried to figure it out. Can you please give me the answer so I can put it on my homework.
Answered by @Steve
My answer is 7w^6-4w^4 it was not correct.
Answered by Steve
(49w^5-28w^3)/7w=
49w^5/7w - 28w^3/7w
= 7w^4 - 4w^2

Why did you add exponents, when I suggested you need to subtract when dividing?

x^a/x^b = x^(a-b)
Answered by @Steve
Thank you so much! Now I get Dividing Binomials by Monomials. Just with understanding how to do one of those math problems I got how to do the others. :)
There are no AI answers yet. The ability to request AI answers is coming soon!